Optimal. Leaf size=117 \[ \frac{16 b^2 (a+b x)^{7/2} (6 A b-13 a B)}{9009 a^4 x^{7/2}}-\frac{8 b (a+b x)^{7/2} (6 A b-13 a B)}{1287 a^3 x^{9/2}}+\frac{2 (a+b x)^{7/2} (6 A b-13 a B)}{143 a^2 x^{11/2}}-\frac{2 A (a+b x)^{7/2}}{13 a x^{13/2}} \]
[Out]
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Rubi [A] time = 0.135993, antiderivative size = 117, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 3, integrand size = 20, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.15 \[ \frac{16 b^2 (a+b x)^{7/2} (6 A b-13 a B)}{9009 a^4 x^{7/2}}-\frac{8 b (a+b x)^{7/2} (6 A b-13 a B)}{1287 a^3 x^{9/2}}+\frac{2 (a+b x)^{7/2} (6 A b-13 a B)}{143 a^2 x^{11/2}}-\frac{2 A (a+b x)^{7/2}}{13 a x^{13/2}} \]
Antiderivative was successfully verified.
[In] Int[((a + b*x)^(5/2)*(A + B*x))/x^(15/2),x]
[Out]
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Rubi in Sympy [A] time = 11.0331, size = 116, normalized size = 0.99 \[ - \frac{2 A \left (a + b x\right )^{\frac{7}{2}}}{13 a x^{\frac{13}{2}}} + \frac{2 \left (a + b x\right )^{\frac{7}{2}} \left (6 A b - 13 B a\right )}{143 a^{2} x^{\frac{11}{2}}} - \frac{8 b \left (a + b x\right )^{\frac{7}{2}} \left (6 A b - 13 B a\right )}{1287 a^{3} x^{\frac{9}{2}}} + \frac{16 b^{2} \left (a + b x\right )^{\frac{7}{2}} \left (6 A b - 13 B a\right )}{9009 a^{4} x^{\frac{7}{2}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate((b*x+a)**(5/2)*(B*x+A)/x**(15/2),x)
[Out]
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Mathematica [A] time = 0.125341, size = 76, normalized size = 0.65 \[ -\frac{2 (a+b x)^{7/2} \left (63 a^3 (11 A+13 B x)-14 a^2 b x (27 A+26 B x)+8 a b^2 x^2 (21 A+13 B x)-48 A b^3 x^3\right )}{9009 a^4 x^{13/2}} \]
Antiderivative was successfully verified.
[In] Integrate[((a + b*x)^(5/2)*(A + B*x))/x^(15/2),x]
[Out]
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Maple [A] time = 0.007, size = 77, normalized size = 0.7 \[ -{\frac{-96\,A{b}^{3}{x}^{3}+208\,B{x}^{3}a{b}^{2}+336\,aA{b}^{2}{x}^{2}-728\,B{x}^{2}{a}^{2}b-756\,{a}^{2}Abx+1638\,{a}^{3}Bx+1386\,A{a}^{3}}{9009\,{a}^{4}} \left ( bx+a \right ) ^{{\frac{7}{2}}}{x}^{-{\frac{13}{2}}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int((b*x+a)^(5/2)*(B*x+A)/x^(15/2),x)
[Out]
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \text{Exception raised: ValueError} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x + A)*(b*x + a)^(5/2)/x^(15/2),x, algorithm="maxima")
[Out]
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Fricas [A] time = 0.26613, size = 201, normalized size = 1.72 \[ -\frac{2 \,{\left (693 \, A a^{6} + 8 \,{\left (13 \, B a b^{5} - 6 \, A b^{6}\right )} x^{6} - 4 \,{\left (13 \, B a^{2} b^{4} - 6 \, A a b^{5}\right )} x^{5} + 3 \,{\left (13 \, B a^{3} b^{3} - 6 \, A a^{2} b^{4}\right )} x^{4} +{\left (1469 \, B a^{4} b^{2} + 15 \, A a^{3} b^{3}\right )} x^{3} + 7 \,{\left (299 \, B a^{5} b + 159 \, A a^{4} b^{2}\right )} x^{2} + 63 \,{\left (13 \, B a^{6} + 27 \, A a^{5} b\right )} x\right )} \sqrt{b x + a}}{9009 \, a^{4} x^{\frac{13}{2}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x + A)*(b*x + a)^(5/2)/x^(15/2),x, algorithm="fricas")
[Out]
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b*x+a)**(5/2)*(B*x+A)/x**(15/2),x)
[Out]
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GIAC/XCAS [A] time = 0.240523, size = 211, normalized size = 1.8 \[ \frac{{\left ({\left (b x + a\right )}{\left (4 \,{\left (b x + a\right )}{\left (\frac{2 \,{\left (13 \, B a^{3} b^{12} - 6 \, A a^{2} b^{13}\right )}{\left (b x + a\right )}}{a^{7} b^{21}} - \frac{13 \,{\left (13 \, B a^{4} b^{12} - 6 \, A a^{3} b^{13}\right )}}{a^{7} b^{21}}\right )} + \frac{143 \,{\left (13 \, B a^{5} b^{12} - 6 \, A a^{4} b^{13}\right )}}{a^{7} b^{21}}\right )} - \frac{1287 \,{\left (B a^{6} b^{12} - A a^{5} b^{13}\right )}}{a^{7} b^{21}}\right )}{\left (b x + a\right )}^{\frac{7}{2}} b}{6642155520 \,{\left ({\left (b x + a\right )} b - a b\right )}^{\frac{13}{2}}{\left | b \right |}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x + A)*(b*x + a)^(5/2)/x^(15/2),x, algorithm="giac")
[Out]